WebSolution Let y = tan –1 (cosec x + cot x) = tan - 1 ( 1 sin x + cos x sin x) = tan - 1 ( 1 + cos x sin x) = tan - 1 [ 2 cos 2 ( x 2) 2 sin ( x ⋅ 2). cos ( x 2)] = tan - 1 [ cot ( x 2)] = tan - 1 [ tan ( π 2 - x 2)] = π 2 - x 2 Differentiating w.r.t. x, we get dy dx d dx dy dx = d dx ( π 2 - x 2) = d dx d dx d dx ( π 2) - 1 2 d dx ( x) = 0 - 1 2 × 1 WebDifferentiate each of the following w.r.t. x : tan^3 x. Class 12. >> Maths. >> Continuity and Differentiability. >> Derivatives of Composite Functions and Chain Rule. >> Differentiate each of the following w.r. Question.

log (sec 3x+tan 3x) - Brainly.in

WebSolution Verified by Toppr Correct option is C) Given y=log(secx+tanx) so, on differentiating the given function with respect to x, we get ⇒ dxdy= (secx+tanx)1 ⋅(secx.tanx+sec 2(x)) ⇒ dxdy = (secx+tanx)1 ⋅secx(tanx+secx) ⇒ dxdy = secx. so the answer of given question is secx. Solve any question of Limits And Derivatives with:- Patterns of problems WebAug 8, 2016 · 4. Determine the missing side lengths in each triangle. You may give an exact answer or round to the nearest tenth. reflective hiking bag

If y = log(sec x + tan x), then dy/dx - Toppr

WebFree Pre-Algebra, Algebra, Trigonometry, Calculus, Geometry, Statistics and Chemistry calculators step-by-step Web( x 3 + 3)3 = dx dx 2 cos x 4 x . cos x ( x 3 + 3)6 vii) log (sec3x + tan3x) dy = Soln: Let, y = log (sec3x + tan3x) dx Differentiate w.r.t. x, ( x 3 + 3) 3 .5( x 3 - 5) 4 (3 x 2 ) - ( x 3 - 5) 5.3( x 3 + 3) 2.(3 x 2 ) dy 1 d ( x3 + 3)6 = (sec3 x + tan 3 x ) × [sec3x + dx dx = tan3x] 15 x 2 ( x3 + 3)3 ( x 3 - 5)4 - 9x 2 ( x 3 + 3)2 ( x3 - 5)5 ... WebFree math problem solver answers your algebra, geometry, trigonometry, calculus, and statistics homework questions with step-by-step explanations, just like a math tutor. reflective holographic clothes