The ph of 0.005 m nh4 2 so4 solution is
WebbpH of 0.01 M (NH4)2 SO4 and 0.02 M NH4OH buffer (pKa of NH+4 = 9.26) is (A) 4.74 + log 2 (B) 4.74 - log 2 (C) 9.26 +log 2 (D) 9.26 + log 1. Check Answ WebbScience Chemistry Calculate the pH and fraction of dissociation (a) for each of the acetic acid (CH,COOH, pK, = 4.756) solutions. A 0.00149 M solution of CH, COOH. pH = 3.78 A 2.87 x 10-12 M solution of CH, COOH. pH = a= a= 1.8 x10-5 Incorrect 0.994. Calculate the pH and fraction of dissociation (a) for each of the acetic acid (CH,COOH, pK, = 4 ...
The ph of 0.005 m nh4 2 so4 solution is
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Webb15 aug. 2010 · N-factor for H2SO4 is 2. So, Molarity=0.02/2=0.01 M This means we have to dissolve 0.01moles of H2SO4 in 1L of water t prepare a 0.02 N solution. 0.01 M H2SO4 = … WebbQ. 20 cm3 of x M solution of HCl is exactly neutralised by 40 cm3 of 0.05 M N aOH solution, the pH of HCl solution is: Q. Calculate the pH at the equivalence point of the …
Webb25 aug. 2024 · The pH of a 0.005 M H SO2 4 solution is _____ - 45854352. anilanilnathreddyu anilanilnathreddyu 27.08.2024 Chemistry Secondary School … WebbQ. 100 mL of 0.005 M H2SO4 is diluted to 1 L. The resulting pH will be . Q. 100 ml of 0.1 M H2SO4 diluted 900 ml of water find the pH of resultant solution. Q. 100mL solution of …
Webb18 juni 2024 · The pH of a 0.005 M H2SO4 solution is Get the answers you need, now! NICKYSCIENTIST27 NICKYSCIENTIST27 20.06.2024 Chemistry Secondary School … WebbQ1. 200 g of aqueous solution of HCl has (w/w)% = 40%. When the solution is left open for sometime in an open atmosphere. HCland water evaporates. The final mass of the solution is 180 g and there is reduction in the weight of HCl by 20%. Calculate the (w/w)% of the final solution. [35.56%] Q2. 100 ml of 0.1 M aqueous solution of NaCl is mixed with 200 ml of …
WebbFor this purpose, solutions of alum and ammonia were alternately added to a flask containing 30 g of 9.66% solution of (NH 4) 2 SO 4 and heated to 90 °C so that the pH was in the range of 6–8.
Webb18 sep. 2024 · Jawab : mol (NH4)2 SO4 = 0,66 / (28+8+32+64) = 0,66 / 132 = 0.005 —–> (mol = grm / Mr) 2NH3 + H2SO4 —-> (NH4)2 SO4 0,01 0.005 Dari reaksi di atas diperoleh mol NH3 = 0,01 mol N2 = 1,12 / 28 = 0,04 Kemudian masukin ke rumus perbandingan : mol NH3 / V NH3 = mol N2 / V N2 0,01 / V NH3 = 0,04 / 1000 V NH3 = 1/4 = 250 ml d diamond and jewelry exchange costa mesaWebbThe pH of a `0.005 M H_(2)SO_(4)` solution is A. `3.3` B. `5.0` C. `2.0` D. `4.0` ... diamond and its usesWebbAnswer (1 of 4): pH pH is defined as the decimal logarithm of the reciprocal of the hydrogen ion activity, a+, in a solution.[3] pH = - log [H+] This solution makes 2 H+ for … diamond and jamboreeWebb13 feb. 2024 · Assuming complete dissociation, calculate the pH of 0.003 M HCl. asked Feb 12, 2024 in Chemistry by SurajKumar (66.2k points) equilibrium; class- 11; Welcome … diamond and jeans partyWebbWhat is the pH of a 0.1 M (N H4)2SO4 ( N H 4) 2 S O 4 solution? pH: One way in which solutions are characterized is on the basis of the acidic or basic nature of the solution. … diamond and jewelry auctioneers in japanWebbAnswer (1 of 3): You have to be careful with polyprotic acids, like sulfuric acid. Although the first H+ of sulfuric acid ionizes 100% (strong acid, Ka1 is very large), the second H+ is a … diamond and jewelry gallery san antonioWebbH2SO4(aq) --> 2H+ + SO4-Since the equation tells us that each molecule of acid will produce 2 hydrogen ions, the concentration of the H+ ion must be 2 x .0050M or .010M … diamond and jim livingston al